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X+3(2X+8)=2X^2+8X+36
We move all terms to the left:
X+3(2X+8)-(2X^2+8X+36)=0
We multiply parentheses
X+6X-(2X^2+8X+36)+24=0
We get rid of parentheses
-2X^2+X+6X-8X-36+24=0
We add all the numbers together, and all the variables
-2X^2-1X-12=0
a = -2; b = -1; c = -12;
Δ = b2-4ac
Δ = -12-4·(-2)·(-12)
Δ = -95
Delta is less than zero, so there is no solution for the equation
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